Mathematics 10 — Exercise Review · Q4 (ii)

Full question

For the following vectors, find 8a+b+5c.

a=2×î−ĵb=3×î+ĵc=4×î+ĵ

Step-by-step solution

  1. Multiply every matrix entry by the scalar.

    (8,[2-1])
  2. Entry (1,1): multiply its value by the scalar.

    8×2=16
  3. Entry (2,1): multiply its value by the scalar.

    8×(-1)=-8
  4. Place the calculated entries in their original row and column positions.

    [16-8]
  5. The orders match. Combine only entries in the same row and column.

    ([16-8],[31])
  6. Entry (1,1): add the corresponding entries.

    16+3=19
  7. Entry (2,1): add the corresponding entries.

    −8+1=-7
  8. Place the calculated entries in their original row and column positions.

    [19-7]
  9. Multiply every matrix entry by the scalar.

    (5,[41])
  10. Entry (1,1): multiply its value by the scalar.

    5×4=20
  11. Entry (2,1): multiply its value by the scalar.

    5×1=5
  12. Place the calculated entries in their original row and column positions.

    [205]
  13. The orders match. Combine only entries in the same row and column.

    ([19-7],[205])
  14. Entry (1,1): add the corresponding entries.

    19+20=39
  15. Entry (2,1): add the corresponding entries.

    −7+5=-2
  16. Place the calculated entries in their original row and column positions.

    [39-2]
  17. The first component multiplies î, the second multiplies ĵ.

    39×î−2×ĵ

Answer

The final answer is shown below.

39×î−2×ĵ