Mathematics 10 — Exercise 5.1 · Q1 (vi)

Full question

Reduce the following algebraic fraction to its lowest terms. State the values of the variables for which the original denominator is zero and exclude them.

20×x3-20×y35×x2+5×x×y+5×y2

Step-by-step solution

  1. The original denominator must be nonzero. Keep this restriction even if a factor is later cancelled.

    5×x2+5×x×y+5×y2≠0
  2. Factor the numerator.

  3. Expand any powers or inner brackets before factoring.

    20×x3-20×y3=20×x3-20×y3
  4. Take the common factor out of every term. Show each remaining term after division.

    20×x3-20×y3=20×(x3-y3)
  5. Apply the matching factor identity: difference of squares, sum/difference of cubes, or grouping. Expand the displayed factors to check the identity.

    20×x3-20×y3=20×(x-y)×(x2+x×y+y2)
  6. The complete factored form is:

    20×(x-y)×(x2+x×y+y2)
  7. Factor the denominator.

  8. Expand any powers or inner brackets before factoring.

    5×x2+5×x×y+5×y2=5×x2+5×x×y+5×y2
  9. Take the common factor out of every term. Show each remaining term after division.

    5×x2+5×x×y+5×y2=5×(x2+x×y+y2)
  10. Apply the matching factor identity: difference of squares, sum/difference of cubes, or grouping. Expand the displayed factors to check the identity.

    5×x2+5×x×y+5×y2=5×(x2+x×y+y2)
  11. The complete factored form is:

    5×(x2+x×y+y2)
  12. Write the factored numerator over the factored denominator.

    20×(x-y)×(x2+x×y+y2)5×(x2+x×y+y2)
  13. This is the common factor of numerator and denominator.

    5×x2+5×x×y+5×y2
  14. Divide numerator and denominator by that same nonzero factor.

    20×x3-20×y35×x2+5×x×y+5×y25×x2+5×x×y+5×y25×x2+5×x×y+5×y2
  15. Simplify the two divisions separately.

    11×(4×x-4×y)
  16. Write the fraction in lowest form. Only factors, never added terms, have been cancelled.

    4×(x-y)

Answer

The final answer is shown below.

4×(x-y)