Mathematics 10 — Exercise 5.2 · Q2

Full question

Subtract 1/(x²+2) FROM (2x³+x²+3)/(x²+2)².

2×x3+x2+3(x2+2)2−1x2+2

Step-by-step solution

  1. Fraction 1: keep its denominator nonzero and factor that denominator.

    (x2+2)2≠0
  2. Fraction 2: keep its denominator nonzero and factor that denominator.

    x2+2≠0
  3. Build the least common denominator from every distinct denominator factor at its largest required power.

    (x2+2)2
  4. For fraction 1, divide the common denominator by its own denominator.

    x4+4×x2+4(x2+2)2=1
  5. Multiply this numerator by the same factor to keep the fraction unchanged.

    1×(2×x3+x2+3)(x2+2)2
  6. For fraction 2, divide the common denominator by its own denominator.

    x4+4×x2+4x2+2=x2+2
  7. Multiply this numerator by the same factor to keep the fraction unchanged.

    -(x2+2)(x2+2)2
  8. The denominators now match. Put all signed numerators over one common denominator.

    1×(2×x3+x2+3)−(x2+2)(x2+2)2
  9. Expand numerator product 1, keeping minus signs on the whole bracket.

    1×(2×x3+x2+3)=2×x3+x2+3
  10. Expand numerator product 2, keeping minus signs on the whole bracket.

    -(x2+2)=-x2-2
  11. Collect like powers and constants in the combined numerator.

    2×x3+x2+3−(x2+2)=2×x3+1
  12. The original denominator must be nonzero. Keep this restriction even if a factor is later cancelled.

    x4+4×x2+4≠0
  13. Factor the numerator.

  14. Factor the denominator.

  15. Expand any powers or inner brackets before factoring.

    x4+4×x2+4=x4+4×x2+4
  16. Apply the matching factor identity: difference of squares, sum/difference of cubes, or grouping. Expand the displayed factors to check the identity.

    x4+4×x2+4=(x2+2)2
  17. The complete factored form is:

    (x2+2)2
  18. Write the factored numerator over the factored denominator.

    2×x3+1(x2+2)2
  19. Write the fraction in lowest form. Only factors, never added terms, have been cancelled.

    2×x3+1(x2+2)2

Answer

The final answer is shown below.

2×x3+1(x2+2)2