Mathematics 10 — Exercise Review · Q2 (iii)

Full question

For the following functions, find fg.

f(x)=25-x2g(x)=x+5

Step-by-step solution

  1. Substitute the function expressions, keeping the brackets.

    (25-x2)×(x+5)
  2. Distribute each bracket product: each term multiplies every term in the other bracket.

    -x3-5×x2+25×x+125
  3. Write EVERY distributed product before collecting terms.

    25×5+25×x+5×(-x2)+x×(-x2)
  4. Calculate this individual product, including its sign and powers.

    25×5=125
  5. Calculate this individual product, including its sign and powers.

    25×x=25×x
  6. Calculate this individual product, including its sign and powers.

    5×(-x2)=-5×x2
  7. Calculate this individual product, including its sign and powers.

    x×(-x2)=-x3
  8. These terms have the same variable part. Add ONLY their coefficients.

    125=125
  9. These terms have the same variable part. Add ONLY their coefficients.

    25=25
  10. These terms have the same variable part. Add ONLY their coefficients.

    -5=-5
  11. These terms have the same variable part. Add ONLY their coefficients.

    -1=-1
  12. Put the simplified groups together.

    125+25×x−5×x2−x3
  13. Collect terms with the same power and simplify their coefficients.

    -x3-5×x2+25×x+125

Answer

The final answer is shown below.

-x3-5×x2+25×x+125