Mathematics 10 — Exercise 4.2 · Q1 (vi)

Full question

Construct a table of values for the following function and use it to draw the graph on a coordinate plane.

f(x)=2×|x+1|-6

Step-by-step solution

  1. The vertex occurs where the expression inside the absolute value is zero.

    x+1=0
  2. Equate the corresponding entries.

    x+1=0
  3. Collect the variable terms on the left and constants on the right.

    x=0−1
  4. Simplify the constant calculation.

    x=-1
  5. Divide both sides by the variable coefficient.

    x=-11
  6. Reduce the fraction.

    x=-1
  7. Substitute the vertex input; |0| = 0, leaving the vertical shift.

    -6=-6
  8. Calculate this operation before combining the remaining terms.

    1×(-4)=-4
  9. Calculate this operation before combining the remaining terms.

    −4+1=-3
  10. Substitute this x into the inside expression.

    1×(-4.0)+1=-3.0
  11. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1−4.0|=0
  12. Calculate this operation before combining the remaining terms.

    1×(-3)=-3
  13. Calculate this operation before combining the remaining terms.

    −3+1=-2
  14. Substitute this x into the inside expression.

    1×(-3.0)+1=-2.0
  15. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1−3.0|=-2.0
  16. Calculate this operation before combining the remaining terms.

    1×(-2)=-2
  17. Calculate this operation before combining the remaining terms.

    −2+1=-1
  18. Substitute this x into the inside expression.

    1×(-2.0)+1=-1.0
  19. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1−2.0|=-4.0
  20. Calculate this operation before combining the remaining terms.

    1×(-1)=-1
  21. Calculate this operation before combining the remaining terms.

    −1+1=0
  22. Substitute this x into the inside expression.

    1×(-1.0)+1=0.0
  23. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1−1.0|=-6
  24. Calculate this operation before combining the remaining terms.

    1×0=0
  25. Calculate this operation before combining the remaining terms.

    0+1=1
  26. Substitute this x into the inside expression.

    1×0.0+1=1.0
  27. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1+0.0|=-4.0
  28. Calculate this operation before combining the remaining terms.

    1×1=1
  29. Calculate this operation before combining the remaining terms.

    1+1=2
  30. Substitute this x into the inside expression.

    1×1.0+1=2.0
  31. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1+1.0|=-2.0
  32. Calculate this operation before combining the remaining terms.

    1×2=2
  33. Calculate this operation before combining the remaining terms.

    2+1=3
  34. Substitute this x into the inside expression.

    1×2.0+1=3.0
  35. Take its absolute value, multiply by the outside factor, then add the shift.

    -6+2×|1+2.0|=0
  36. Plot the table points and join them with the two straight arms of the V-shaped graph.

xf(x)
-4.00
-3.0-2.00000000000000
-2.0-4.00000000000000
-1.0-6
0.0-4.00000000000000
1.0-2.00000000000000
2.00

Answer

The final answer is shown below.

vertex=(-1.0,-6)-5-4-3-2-10123-6-4-202xy(-4, 0)(-3, -2)(-2, -4)(-1, -6)(0, -4)(1, -2)(2, 0)