Mathematics 10 — Exercise 2.3 · Q8
Full question
If α,β are roots of x² + ax + b = 0 and α²,β² are roots of x² + Ax + B = 0, prove A = 2b − a², B = b².
Step-by-step solution
Original sum α+β = −a and product αβ = b.
Expand (α+β)² = α²+2αβ+β², so the new sum is α²+β² = a²−2b.
The coefficient A is minus this sum: A = −(a²−2b) = 2b−a².
The new product is α²β² = (αβ)² = b², so B = b².
Answer
The final answer is shown below.