Mathematics 10 — Exercise 2.1 · Q2 (iv)

Full question

Solve the following quadratic equation by factorization method: x²-3 × x/2 = 9/2.

x2−3×x2=92

Step-by-step solution

  1. A denominator cannot equal zero. Keep the original excluded values throughout the calculation.

    2≠0
  2. Multiply BOTH sides by the common denominator to remove the fractions.

    2×(x2-3×x2)=2×92
  3. Expand the brackets and subtract the right-hand terms from both sides. Collect powers of the variable.

    2×x2-3×x-9=0
  4. Split the middle coefficient into two numbers whose sum is b and whose product is a·c.

    (3−6=-3,3×(-6)=-18)
  5. Rewrite the middle term using those two parts.

    2×x2+3×x−6×x−9=0
  6. Group the first two terms and the last two. Take out the common factor from each group.

    x×(2×x+3)−3×(2×x+3)=0
  7. The common bracket can now be factored out.

    (x-3)×(2×x+3)=0
  8. A product is zero only if at least one factor is zero. Set each linear factor equal to zero.

    (x-3=0,2×x+3=0)
  9. Take this factor equal to zero.

    x-3=0
  10. Subtract the constant from both sides.

    x−3+3=0+3
  11. Simplify both sides.

    x=3
  12. Divide both sides by the coefficient of the variable.

    x=3×11
  13. Reduce the fraction to obtain this root.

    x=3
  14. Take this factor equal to zero.

    2×x+3=0
  15. Subtract the constant from both sides.

    2×x+3−3=0−3
  16. Simplify both sides.

    2×x=-3
  17. Divide both sides by the coefficient of the variable.

    x=-32
  18. Reduce the fraction to obtain this root.

    x=-32
  19. Substitute this root into the original equation before simplifying.

    92=92
  20. Calculate both sides; their equal values confirm the root.

    92=92
  21. Substitute this root into the original equation before simplifying.

    92=92
  22. Calculate both sides; their equal values confirm the root.

    92=92

Answer

The final answer is shown below.

{-32,3}