Mathematics 10 — Exercise 12.2 · Q14 (i)

Full question

P(A)=0.42,P(B)=0.48,P(A∩B)=0.16. Find P(not A).

Step-by-step solution

  1. An event and its complement have total probability 1. Subtract the event probability from 1.

  2. For multiplication of fractions, multiply the numerators together and the denominators together.

    21×11×50
  3. Calculate these two products separately.

    2150
  4. Calculate this operation before combining the remaining terms.

    21×150=2150
  5. For multiplication of fractions, multiply the numerators together and the denominators together.

    (-1)×211×50
  6. Calculate this operation before combining the remaining terms.

    (-1)×2150=-2150
  7. Substitute the given probabilities or outcome counts.

    1−2150
  8. To add these fractions, first use a common denominator: the least common multiple of their denominators.

    LCD=50
  9. Multiply this numerator AND denominator by the same factor. Its value stays unchanged.

    11=1×501×50
  10. Calculate the converted numerator; the denominator is now common.

    5050
  11. For multiplication of fractions, multiply the numerators together and the denominators together.

    (-21)×11×50
  12. Calculate this operation before combining the remaining terms.

    (-21)×150=-2150
  13. Multiply this numerator AND denominator by the same factor. Its value stays unchanged.

    -2150=(-21)×150×1
  14. Calculate the converted numerator; the denominator is now common.

    -2150
  15. Calculate this operation before combining the remaining terms.

    (-1)×21=-21
  16. Calculate this operation before combining the remaining terms.

    50−21=29
  17. For multiplication of fractions, multiply the numerators together and the denominators together.

    29×11×50
  18. Calculate these two products separately.

    2950
  19. Calculate this operation before combining the remaining terms.

    29×150=2950
  20. Keep the common denominator and add the signed numerators.

    50−2150=2950
  21. Calculate this operation before combining the remaining terms.

    1−2150=2950
  22. The simplified result is the required probability.

    2950

Answer

The final answer is shown below.

2950