Mathematics 10 — Exercise 1.4 · Q2 (iii)

Full question

Solve the simultaneous equations for complex numbers z and w.

-4×w+z=3×i3×w+2×z=11-5×i

Step-by-step solution

  1. We have two equations for the two unknown complex numbers z and w.

    (-4×w+z=3×i,3×w+2×z=11-5×i)
  2. Multiply the first equation by the coefficient of w in the second, and the second by the coefficient of w in the first.

    (-12×w+3×z=9×i,-12×w-8×z=20×i-44)
  3. Subtract. Both w terms cancel. Expand the remaining coefficients using i² = −1.

    11×z=44-11×i
  4. Start with the original quotient. For an inverse, the numerator is 1.

    44-11×i11
  5. Find the conjugate of the denominator: keep its real part and reverse the imaginary sign.

    11
  6. Multiply by the conjugate over itself; this fraction equals 1.

    (1111)×(44-11×i11)
  7. Multiply numerators together and denominators together. Keep their brackets intact.

    11×(44-11×i)11×11
  8. Calculate the numerator first.

  9. Distribute the first bracket: multiply its real term by the whole second bracket, then its imaginary term by that bracket.

    44×11−11×11×i
  10. Distribute each of those products. Keep all four multiplications visible.

    44×11+44×0×i−11×11×i−11×0×ii
  11. Real × real: multiply the numerical coefficients.

    44×11=484
  12. Real × imaginary: multiply the numerical coefficients.

    44×0×i=0×i
  13. Imaginary × real: multiply the numerical coefficients.

    -11×11×i=-121×i
  14. Imaginary × imaginary: multiply the numerical coefficients.

    -11×0×ii=0×i2
  15. Substitute these four products into the expansion.

    484+0×i−121×i+0×i2
  16. In the last term replace i² by −1.

    0×i2=0×(-1)
  17. Multiply its coefficient by −1.

    0×(-1)=0
  18. Rewrite the expansion after this sign calculation.

    484+0×i−121×i+0
  19. Group the real terms and factor i out of the imaginary terms.

    484+0+i×(0−121)
  20. Calculate the sum of the real terms.

    484+0=484
  21. Calculate the sum of the imaginary coefficients.

    0−121=-121
  22. Insert both calculated sums in a + bi form.

    484-121×i
  23. Now calculate the denominator independently.

  24. Distribute the first bracket: multiply its real term by the whole second bracket, then its imaginary term by that bracket.

    11×11+0×11×i
  25. Distribute each of those products. Keep all four multiplications visible.

    11×11+11×0×i+0×11×i+0×0×ii
  26. Real × real: multiply the numerical coefficients.

    11×11=121
  27. Real × imaginary: multiply the numerical coefficients.

    11×0×i=0×i
  28. Imaginary × real: multiply the numerical coefficients.

    0×11×i=0×i
  29. Imaginary × imaginary: multiply the numerical coefficients.

    0×0×ii=0×i2
  30. Substitute these four products into the expansion.

    121+0×i+0×i+0×i2
  31. In the last term replace i² by −1.

    0×i2=0×(-1)
  32. Multiply its coefficient by −1.

    0×(-1)=0
  33. Rewrite the expansion after this sign calculation.

    121+0×i+0×i+0
  34. Group the real terms and factor i out of the imaginary terms.

    121+0+i×(0+0)
  35. Calculate the sum of the real terms.

    121+0=121
  36. Calculate the sum of the imaginary coefficients.

    0+0=0
  37. Insert both calculated sums in a + bi form.

    0×i+121
  38. The imaginary coefficient in the denominator is zero, so the denominator is real.

    121=121
  39. Put the calculated numerator above the calculated denominator.

    484-121×i121
  40. Separate the real term and imaginary term into two fractions with the same denominator.

    484121+-121×i121
  41. Move i outside its numerical fraction.

    484121+(-121121)×i
  42. Reduce the real coefficient by dividing numerator and denominator by 121.

    484121=484121121121
  43. Simplify the real coefficient fraction.

    484121=4
  44. For multiplication of fractions, multiply the numerators together and the denominators together.

    (-121)×11×121
  45. Calculate these two products separately.

    -121121
  46. The numerator and denominator have this greatest common divisor. Divide BOTH by it.

    GCD=121
  47. Show the two divisions explicitly.

    -121121121121
  48. Evaluate the denominator division.

    121121=1
  49. Write the reduced fraction.

    -11
  50. Calculate this operation before combining the remaining terms.

    (-121)×1121=-1
  51. Reduce the imaginary coefficient by dividing numerator and denominator by 121.

    -121121=-121121121121
  52. Simplify the imaginary coefficient fraction.

    -121121=-1
  53. Combine the reduced real and imaginary terms.

    4-i
  54. This quotient is z. Substitute it into the first original equation.

    -i-4×w+4=3×i
  55. Subtract the known z term from both sides, then divide by the coefficient of w.

    -4×w=4×i-4
  56. Start with the original quotient. For an inverse, the numerator is 1.

    4×i-4-4
  57. Find the conjugate of the denominator: keep its real part and reverse the imaginary sign.

    -4
  58. Multiply by the conjugate over itself; this fraction equals 1.

    (-4-4)×(4×i-4-4)
  59. Multiply numerators together and denominators together. Keep their brackets intact.

    (-4)×(4×i-4)(-4)×(-4)
  60. Calculate the numerator first.

  61. Distribute the first bracket: multiply its real term by the whole second bracket, then its imaginary term by that bracket.

    −-16+4×(-4)×i
  62. Distribute each of those products. Keep all four multiplications visible.

    −-16−0×i+4×(-4)×i+4×0×ii
  63. Real × real: multiply the numerical coefficients.

    (-4)×(-4)=16
  64. Real × imaginary: multiply the numerical coefficients.

    -0×i=0×i
  65. Imaginary × real: multiply the numerical coefficients.

    4×(-4)×i=-16×i
  66. Imaginary × imaginary: multiply the numerical coefficients.

    4×0×ii=0×i2
  67. Substitute these four products into the expansion.

    16+0×i−16×i+0×i2
  68. In the last term replace i² by −1.

    0×i2=0×(-1)
  69. Multiply its coefficient by −1.

    0×(-1)=0
  70. Rewrite the expansion after this sign calculation.

    16+0×i−16×i+0
  71. Group the real terms and factor i out of the imaginary terms.

    16+0+i×(0−16)
  72. Calculate the sum of the real terms.

    16+0=16
  73. Calculate the sum of the imaginary coefficients.

    0−16=-16
  74. Insert both calculated sums in a + bi form.

    16-16×i
  75. Now calculate the denominator independently.

  76. Distribute the first bracket: multiply its real term by the whole second bracket, then its imaginary term by that bracket.

    −-16+0×(-4)×i
  77. Distribute each of those products. Keep all four multiplications visible.

    −-16−0×i+0×(-4)×i+0×0×ii
  78. Real × real: multiply the numerical coefficients.

    (-4)×(-4)=16
  79. Real × imaginary: multiply the numerical coefficients.

    -0×i=0×i
  80. Imaginary × real: multiply the numerical coefficients.

    0×(-4)×i=0×i
  81. Imaginary × imaginary: multiply the numerical coefficients.

    0×0×ii=0×i2
  82. Substitute these four products into the expansion.

    16+0×i+0×i+0×i2
  83. In the last term replace i² by −1.

    0×i2=0×(-1)
  84. Multiply its coefficient by −1.

    0×(-1)=0
  85. Rewrite the expansion after this sign calculation.

    16+0×i+0×i+0
  86. Group the real terms and factor i out of the imaginary terms.

    16+0+i×(0+0)
  87. Calculate the sum of the real terms.

    16+0=16
  88. Calculate the sum of the imaginary coefficients.

    0+0=0
  89. Insert both calculated sums in a + bi form.

    0×i+16
  90. The imaginary coefficient in the denominator is zero, so the denominator is real.

    16=16
  91. Put the calculated numerator above the calculated denominator.

    16-16×i16
  92. Separate the real term and imaginary term into two fractions with the same denominator.

    1616+-16×i16
  93. Move i outside its numerical fraction.

    1616+(-1616)×i
  94. Reduce the real coefficient by dividing numerator and denominator by 16.

    1616=16161616
  95. Simplify the real coefficient fraction.

    1616=1
  96. For multiplication of fractions, multiply the numerators together and the denominators together.

    (-16)×11×16
  97. Calculate these two products separately.

    -1616
  98. The numerator and denominator have this greatest common divisor. Divide BOTH by it.

    GCD=16
  99. Show the two divisions explicitly.

    -16161616
  100. Calculate this operation before combining the remaining terms.

    (-16)×116=-1
  101. Reduce the imaginary coefficient by dividing numerator and denominator by 16.

    -1616=-16161616
  102. Simplify the imaginary coefficient fraction.

    -1616=-1
  103. Combine the reduced real and imaginary terms.

    1-i
  104. Check z and w in both original equations.

    (3×i=3×i,11-5×i=11-5×i)

Answer

The final answer is shown below.

z=4-iw=1-i