Mathematics 10 — Exercise Review · Q3, a

Full question

SQ is a diameter; PSQ=42°, QSR=72°. Find a=SPQ.

OSQPR∠PSQ=42°; ∠QSR=72°a=SPQ; b=SRQ; c=PQS; d=SQRDiagram not to scale

Step-by-step solution

  1. An angle subtended by a diameter is 90°.

  2. Substitute the given numbers into the formula.

    90

  3. The required result is shown below. Unit: °

    90

Answer

The final answer is shown below.

90