Mathematics 10 — Exercise 9.1 · Q3 (i)

Full question

AC is a diameter and DE is tangent at C. Angle BCD=62°. Find angle BCA.

Step-by-step solution

1. AC is perpendicular to the tangent. Angle ACD=90°. BCA and BCD together form that angle.

2. Substitute the given numbers into the formula.

   $$90-62$$

3. Calculate this operation before combining the remaining terms.

   $$90-62=28$$

4. The required result is shown below. Unit: °

   $$28$$

Answer

The final answer is shown below.