Mathematics 10 — Exercise 7.2 · Q1 (iv)

Full question

Using the following measurements, solve triangle ABC by finding all its unknown sides and angles. If two triangles are possible, give both solutions.

b (cm)=4.8a (cm)=4B (°)=71

Step-by-step solution

  1. Use the sine law to find the sine of the angle opposite the other given side.

    sin(A°)=4.0×sin(71.0°)4.8
  2. Evaluate the sine, multiply the numerator, then divide by the known opposite side.

    sin(A°)=0.78793215
  3. Inverse sine gives one angle; its supplement has the same sine. Check BOTH against the 180° angle sum.

    (51.992685,128.00731)
  4. For this valid branch subtract both known angles from 180°.

    C=57.007315
  5. Reject this supplement: the known angles would sum to at least 180°.

    128.00731
  6. Rearrange the sine law to isolate the missing side.

    c=4.8×sin(57.00731489182614°)sin(71.0°)
  7. Evaluate both sines and multiply the known side by the numerator sine.

    c=4.02595250.94551858
  8. Divide by the denominator sine.

    c=4.2579306

Answer

The final answer is shown below.

b (cm)=4.8a (cm)=4.0c (cm)=4.2579306B (°)=71.0A (°)=51.992685C (°)=57.007315ABCa=4.000 cmb=4.800 cmc=4.258 cm