Mathematics 10 — Exercise 7.2 · Q1 (i)

Full question

Using the following measurements, solve triangle ABC by finding all its unknown sides and angles. If two triangles are possible, give both solutions.

a (cm)=6.1b (cm)=8.4A (°)=42

Step-by-step solution

  1. Use the sine law to find the sine of the angle opposite the other given side.

    sin(B°)=8.4×sin(42.0°)6.1
  2. Evaluate the sine, multiply the numerator, then divide by the known opposite side.

    sin(B°)=0.92142575
  3. Inverse sine gives one angle; its supplement has the same sine. Check BOTH against the 180° angle sum.

    (67.135415,112.86458)
  4. For this valid branch subtract both known angles from 180°.

    C=70.864585
  5. For this valid branch subtract both known angles from 180°.

    C=25.135415
  6. Rearrange the sine law to isolate the missing side.

    c=6.1×sin(70.86458460526921°)sin(42.0°)
  7. Evaluate both sines and multiply the known side by the numerator sine.

    c=5.76295350.66913061
  8. Divide by the denominator sine.

    c=8.6125989
  9. Rearrange the sine law to isolate the missing side.

    c=6.1×sin(25.135415394730785°)sin(42.0°)
  10. Evaluate both sines and multiply the known side by the numerator sine.

    c=2.59103040.66913061
  11. Divide by the denominator sine.

    c=3.8722342

Answer

The final answer is shown below.

a (cm)=6.1b (cm)=8.4c (cm)=8.6125989A (°)=42.0B (°)=67.135415C (°)=70.864585a (cm)=6.1b (cm)=8.4c (cm)=3.8722342A (°)=42.0B (°)=112.86458C (°)=25.135415ABCa=6.100 cmb=8.400 cmc=8.613 cmABCa=6.100 cmb=8.400 cmc=3.872 cm