Mathematics 10 — Exercise Review · Q1 (ix)
Full question
Find roots of y²−24y+128=0.
| Option | Value |
|---|---|
| a | 8,−16 |
| b | 8,16 |
| c | −8,16 |
| d | −8,−16 |
Step-by-step solution
−8−16=−24 and (−8)(−16)=128, so (y−8)(y−16)=0.
Answer
(b) 8,16
Find roots of y²−24y+128=0.
| Option | Value |
|---|---|
| a | 8,−16 |
| b | 8,16 |
| c | −8,16 |
| d | −8,−16 |
−8−16=−24 and (−8)(−16)=128, so (y−8)(y−16)=0.
(b) 8,16