Mathematics 10 — Exercise Review · Q1 (vi)
Full question
Simplify (x³−y³)÷(x−y).
| Option | Value |
|---|---|
| a | x²−xy+y² |
| b | x²+xy+y² |
| c | x²−y² |
| d | x²+y² |
Step-by-step solution
Use x³−y³=(x−y)(x²+xy+y²), where x≠y.
Answer
(b) x²+xy+y²
Simplify (x³−y³)÷(x−y).
| Option | Value |
|---|---|
| a | x²−xy+y² |
| b | x²+xy+y² |
| c | x²−y² |
| d | x²+y² |
Use x³−y³=(x−y)(x²+xy+y²), where x≠y.
(b) x²+xy+y²