Mathematics 10 — Exercise 2.7 · Q5

Full question

A ball is thrown upward at 40 m/s. Find its maximum height above ground.

Step-by-step solution

1. At the highest point final velocity is 0. Use g = 10 m/s² downward, as in the textbook examples.

2. Use v² = u² − 2gh and put v = 0, u = 40.

   $$0=1600-20\times h$$

3. Add 20h to both sides, then divide by 20.

   $$(20\times h=1600,h=80)$$

Answer

The final answer is shown below.