Mathematics 10 — Exercise 2.3 · Q4 (v)

Full question

If α,β are roots of x² + 2x + 4 = 0, form the equation with the displayed new roots.

Step-by-step solution

1. For the original monic equation, sum of roots = −linear coefficient and product = constant.

   $$(\alpha +\beta =-2,\alpha \times \beta =4)$$

2. Add the two required roots to obtain their new sum.

   $$\mathrm{Sum}=-6$$

3. Multiply the two required roots to obtain their new product.

   $$\mathrm{Product}=21$$

4. A monic quadratic with roots r₁,r₂ is x² − (sum)x + product = 0. Substitute the two values.

   $$x^2+6\times x+21=0$$

Answer

The final answer is shown below.