Mathematics 10 — Exercise Review · Q3
Full question
One card is drawn at random from a standard deck of 52 playing cards. Find the probability that the card is an ace or a spade.
Step-by-step solution
For an inclusive OR, add the two probabilities and subtract their overlap once: P(A∪B)=P(A)+P(B)−P(A∩B).
There are 4 aces,13 spades, and ONE ace of spades in the overlap.
Calculate this operation before combining the remaining terms.
Substitute the given probabilities or outcome counts.
Calculate this operation before combining the remaining terms.
Calculate this operation before combining the remaining terms.
Calculate this operation before combining the remaining terms.
For multiplication of fractions, multiply the numerators together and the denominators together.
Calculate these two products separately.
The numerator and denominator have this greatest common divisor. Divide BOTH by it.
For multiplication of fractions, multiply the numerators together and the denominators together.
Calculate these two products separately.
Show the two divisions explicitly.
Evaluate the denominator division.
Write the reduced fraction.
Calculate this operation before combining the remaining terms.
For multiplication of fractions, multiply the numerators together and the denominators together.
Calculate these two products separately.
Show the two divisions explicitly.
Write the reduced fraction.
Calculate this operation before combining the remaining terms.
For multiplication of fractions, multiply the numerators together and the denominators together.
Calculate this operation before combining the remaining terms.
Show the two divisions explicitly.
Evaluate the numerator division.
Evaluate the denominator division.
Write the reduced fraction.
For multiplication of fractions, multiply the numerators together and the denominators together.
Calculate these two products separately.
Calculate this operation before combining the remaining terms.
Calculate this operation before combining the remaining terms.
The simplified result is the required probability.
Answer
The final answer is shown below.