Mathematics 10 — Exercise 1.3 · Q2 (i)

Full question

For the given z₁,z₂, verify the displayed conjugate property.

z₁=7×i+2z₂=4-3×iz₁+z₂=z₁+z₂

Step-by-step solution

  1. Write both complex numbers with their real and imaginary parts.

    7×i+2−(3×i-4)
  2. Remove the brackets, preserving the signs of all four terms.

    2+7×i+4−3×i
  3. Place the real terms together. Factor i out of the imaginary terms.

    2+4+i×(7−3)
  4. Calculate the real part only.

    2+4=6
  5. Calculate the imaginary coefficient only.

    7−3=4
  6. Put these two results into a + bi form.

    4×i+6
  7. Take the conjugate of that result by changing the sign of its imaginary coefficient.

    6-4×i
  8. Now combine the conjugates of the original numbers independently.

  9. Write both complex numbers with their real and imaginary parts.

    −(7×i-2)+3×i+4
  10. Remove the brackets, preserving the signs of all four terms.

    2−7×i+4+3×i
  11. Place the real terms together. Factor i out of the imaginary terms.

    2+4+i×(−7+3)
  12. Calculate the real part only.

    2+4=6
  13. Calculate the imaginary coefficient only.

    −7+3=-4
  14. Put these two results into a + bi form.

    6-4×i
  15. Both results are equal.

    6-4×i=6-4×i

Answer

The final answer is shown below.

6-4×i