Mathematics 10 — Exercise 1.2 · Q6

Full question

Find the real values of x and y that satisfy the following equality of complex numbers.

(1-i)×(i×y+2×x)=2×i+4

Step-by-step solution

  1. Expand the brackets and replace i² by −1.

    -2×i×x+i×y+2×x+y=2×i+4
  2. Equal complex numbers have equal real parts and equal coefficients of i. Match these separately.

    (2×x+y=4,-2×x+y=2)
  3. Eliminate the second variable by multiplying the first equation by its coefficient in the second, and the second equation by its coefficient in the first.

    (2×x+y=4,-2×x+y=2)
  4. Subtract these equations. The second-variable terms cancel.

    4×x=2
  5. Divide by the remaining coefficient to find the first variable.

    x=12
  6. Substitute the first value into an equation containing the second variable.

    2×12+y=4
  7. Calculate the known product.

    y+1=4
  8. Subtract the known term from both sides.

    y=4−1
  9. Simplify the subtraction.

    y=3
  10. Divide by the coefficient.

    y=3×11
  11. Simplify this fraction.

    y=3
  12. Check both values in the original complex equation.

    2×i+4=2×i+4

Answer

The final answer is shown below.

x=12y=3