Mathematics 10 — Exercise 1.1 · Q3 (v)

Full question

Find the real values of x and y that satisfy the following equality of complex numbers.

i×(2×y-3)+3×x-1=7×i+8

Step-by-step solution

  1. Expand the brackets and replace i² by −1.

    2×i×y-3×i+3×x-1=7×i+8
  2. Equal complex numbers have equal real parts and equal coefficients of i. Match these separately.

    (3×x-1=8,2×y-3=7)
  3. Use the equation containing only the first variable.

    3×x-1=8
  4. Subtract the constant term from both sides.

    3×x−1+1=8+1
  5. Simplify the subtraction.

    3×x=9
  6. Divide both sides by the coefficient.

    x=93
  7. Simplify the fraction.

    x=3
  8. Use the other original equation to find the second variable.

    2×y-3=7
  9. Subtract the constant from both sides.

    2×y-3+3=7+3
  10. Simplify the two sides.

    2×y=10
  11. Divide both sides by the coefficient.

    y=102
  12. Simplify to find the second value.

    y=5
  13. Check both values in the original complex equation.

    7×i+8=7×i+8

Answer

The final answer is shown below.

x=3y=5