Mathematics 10 — Exercise Review · Q9

Full question

Find the real values of a and b that satisfy the following equation.

(3-4×i)×(a+b×i)=1

Step-by-step solution

  1. Expand the brackets and replace i² by −1.

    -4×a×i+3×a+3×b×i+4×b=1
  2. Equal complex numbers have equal real parts and equal coefficients of i. Match these separately.

    (3×a+4×b=1,-4×a+3×b=0)
  3. Eliminate the second variable by multiplying the first equation by its coefficient in the second, and the second equation by its coefficient in the first.

    (9×a+12×b=3,-16×a+12×b=0)
  4. Subtract these equations. The second-variable terms cancel.

    25×a=3
  5. Divide by the remaining coefficient to find the first variable.

    a=325
  6. Substitute the first value into an equation containing the second variable.

    3×325+4×b=1
  7. Calculate the known product.

    4×b+925=1
  8. Subtract the known term from both sides.

    4×b=1−925
  9. Simplify the subtraction.

    4×b=1625
  10. Divide by the coefficient.

    b=16100
  11. Simplify this fraction.

    b=425
  12. Check both values in the original complex equation.

    1=1

Answer

The final answer is shown below.

a=325b=425