PHYSICS 10 SCIENCE · 2026–27 · E · Worked numericals · QUESTION 14.2 · EM p. 87

A ray in air (n₁=1.0) strikes glass (n₂=1.5) at 30°. Find the refraction angle.

ہوا n₁=1.0 سے شیشہ n₂=1.5 میں زاویۂ سقوط30°؛ زاویۂ انکسار نکالیں۔

Solution & explanation

  1. Given: i = 30°; n₁ = 1; n₂ = 1.5.

  2. Use Snell’s law; angles are measured from the normal.

    n1×sin(i)=n2×sin(r)
  3. Divide both sides by n₂.

    sin(r)=n1×sin(i)n2
  4. Substitute and evaluate the sine in degree mode.

    sin(r)=sin(30×π180)1.5
  5. Take inverse sine to obtain r, not merely sin r.

    r=180×arcsin(sin(30×π180)1.5)π
  6. The angle is approximately 19.4712 degrees.

  7. State the result with units: r ≈ 19.47°

Air to glass refraction bends light toward the normalAir: lower nGlass: higher nNormalirr < i
Schematic · not to scale

r ≈ 19.47°

Independent study answer. Original textbook ↗ · English-medium printed page 87.