PHYSICS 10 SCIENCE · 2026–27 · E · Worked numericals · QUESTION 13.1 · EM p. 61

At a particular temperature, sound speed is 333 m s⁻¹ and wavelength is 3 cm. Calculate frequency and say whether it is typically audible.

آواز کی رفتار333 m s⁻¹، طول3 cm۔ تعدد اور انسانی سماعت میں ہونا بتائیں۔

Solution & explanation

  1. Given: v = 333 m s⁻¹; λ = 3 cm.

  2. Find: f in Hz

  3. Convert centimetres to metres.

    λ=3100=0.03
  4. Start with v = fλ.

    v=f×λ
  5. Divide both sides by wavelength.

    f=vλ
  6. Substitute speed and wavelength.

    f=3330.03
  7. Perform the division.

    f=11100.0
  8. State the result with units: f = 11100 Hz = 11.1 kHz

  9. Compare with approximately 20–20000 Hz. This frequency lies inside that range.

f = 11100 Hz = 11.1 kHz; within the typical audible range.

Independent study answer. Original textbook ↗ · English-medium printed page 61.